Question

Repede va rog, pls. Coroana ​

Answer 1

(2x+3)/4-(2x+1)/12=(x-3)/6-(2x+1)/3+x/4

3(2x+3)/12-(2x+1)/12=2(x-3)/12-4(2x+1)/12+3x/12

3(2x+3)-(2x+1)=2(x-3)-4(2x+1)+3x

6x+9-2x-1=2x-6-8x-4+3x

4x+8= -3x-10

4x+3x= -10-8

7x= -18

x= -18/7

Answer 2

Facem numitor comun, apoi vom inmulti in treaga relatie obtinuta, pentru a scapa de fractii. Prima fractie de amplifica cu 3, a doua nu se amplifica, a treia cu 2, a patra cu 4 si a cincea cu 3. Cand vom inmulti intreaga relatie obtinuta dupa amplificare, va trebui sa avem grija unde avem minus in fata fractiei, deoarece se vor schimba semnele.

$\frac{2x+3}{4}- \frac{2x+1}{12}= \frac{x-3}{6}- \frac{2x+1}{3}+\frac{x}{4} \\\\\frac{6x+9}{12} -\frac{2x+1}{12}=\frac{2x-6}{12}-\frac{8x+4}{12} +\frac{3x}{12} |*12\\\\6x+9-2x-1=2x-6-8x-4+3x\\\\4x+8= -3x-10\\\\4x+3x=-10-8\\\\7x=-18\\\\x=-\frac{18}{7}$