Question

Restrangeti:   (sa imi rezolvati desfasurat)
a)√36-√2-(√8+1)-(1-3√2)
b)√3-[(3√3-√8)-(√18-√2)]
c)√45-√75-(√2+1)-(1-5√3)+(4-3√5)
d)(3√8-3√18+3√3)-[6√2-(√18-√3)]
e)-(4√80-2√8-√9)-(2√32-7√5+4)+1

Answer 1

[tex]a).\;\sqrt{36}=6\;;\;\sqrt{8}=\sqrt{2^2*2}=2\sqrt2\;;\\ \Rightarrow\;\;6-\underline{\sqrt2}-\underline{2\sqrt2}-1-1+\underline{3\sqrt2}=4\;;\\ b).\;\sqrt3-[(3\sqrt3-\sqrt8)-(\sqrt{18}-\sqrt2)]=\\ \;\;\;\;\;=\sqrt3-(3\sqrt3-2\sqrt2-3\sqrt2+\sqrt2)=\sqrt3-3\sqrt3+2\sqrt2+3-\sqrt2=\\ \;\;\;=-2\sqrt3+\sqrt2+3\;;\\ [/tex]Scrie răspunsul tău aici