Question

Restul impartirii la 10 a numarului 2018^2021 +2019^2020+2020^2019 este?

Answer 1

$U(2018^{2021} +2019^{2020} +2020^{2019})=$

$U(8^{2021} +9^{2020} +0^{2019})=$

$U(64^{1010}\cdot8 +81^{1010} +0)=$

$U(4^{1010}\cdot8 +1^{1010} )=$

$U(16^{505}\cdot8 +1 )=$

$U(6\cdot8 +1 )=$

$U(48 +1 )=$

$\boxed{ 9}$

Restul impartirii la 10 a numarului 2018^2021 +2019^2020+2020^2019 va fi 9