Question

Revolvati in multimea numerelor intregi ecuatiile: a) 3(2x+1)-4(x+3)=5-2(2x+1); b) 5x-6-3(x+4)=3(x-5)-7; c) 2[15-4(3x-8)]-7=3[18-5(2x-3)]+18​

Answer 1

Răspuns:

Explicație pas cu pas:

a) 3(2x+1)-4(x+3)=5-2(2x+1)

6x+3-4x-12=5-4x-2

6x-4x=5-2+12-3

6x=12

x=2

b) 5x-6-3(x+4)=3(x-5)-7

5x-6-3x-12=3x-15-7

5x-3x+3x=-15-7+12+6

-x=-4

x=4

c) 2[15-4(3x-8)]-7=3[18-5(2x-3)]+18

2[15-12x+32]-7=3[18-5(2x-3)]+18

2(47-22x)-7=3(33-10x)+18

94-24x-7=117-30x

-24x+30x=117-87

6x=30

x=5