Question

Rezolva ecuatia :
(5-radical din 7)x-5-radical din 7=0

Answer 1

$(5 - \sqrt{7} )x - 5 - \sqrt{7} = 0$

$(5 - \sqrt{7} )x = 5 + \sqrt{7}$

$x = \frac{5 + \sqrt{7} }{5 - \sqrt{7} }$

$x = \frac{ {(5 + \sqrt{7} )}^{2} }{(5 - \sqrt{7})(5 + \sqrt{7} )}$

$x = \frac{25 + 10 \sqrt{7} + 7 }{25 - 7}$

$x = \frac{32 + 10 \sqrt{7} }{18}$

$x = \frac{2(16 + 5 \sqrt{7} )}{18}$

$x = \frac{16 + 5 \sqrt{7} }{9}$