Question

rezolva ecuatia
multumesc mult​

Answer 1

$\it 2x^2-9x+10=0 \Rightarrow 2x^2-5x-4x+10=0 \Rightarrow x(2x-5)-2(2x-5)=0 \Rightarrow \\ \\ \Rightarrow (2x-5)(x-2)=0 \Rightarrow \begin{cases}\it x-2=0 \Rightarrow x_1=2\\ \\ \it 2x-5=0 \Rightarrow 2x=5 \Rightarrow x_2=\dfrac{5}{2}=2,5\end{cases}$