Question

rezolva prin metoda gauss
a)1+2+3+...7001
b)1+2+3+...2010​

Answer 1

$1+2+3+...7001 =$

Formula Gauss:

$[(1+n )\cdot n] : 2$

$[(1 + 7001)\cdot 7001] : 2 =$

$(7002 \cdot 7001) : 2$

$49021002 : 2 = 24510501$

$1+2+3+...2010 =$

$[(1 + 2010)\cdot 2010] : 2 =$

$(2011 \cdot 2010) : 2 =$

$4042110: 2 = 2021055$