Question

rezolva sistemul de ecuati prin reducere 2(x+2y)-8=x+2 si 3(1-2x)-4y=-17​

Answer 1

2x+4y-8=x+2

x+4y=2+8

x+4y=10

3-6x-4y=-17

-6x-4y=-20

-2(3x+2y)=-20

P.S nustiu daca era nevoie neaparat de factor comun la ultima parte

Answer 2

Răspuns:

2x + 4y - 8 = x + 2

3 - 6x - 4y = -17

2x + 4y - x = 2 + 8

x + 4y = 10 (1)

-6x - 4y = -17 -3

-6x - 4y = -20 (2)

x + 4y = 10 (×6)

-6x - 4y = - 20

6x + 24y = 60

-6x - 4y = -20

20y = 40

y = 2

il scoatem pe x din prima ecuatie

x + 4(2) = 10

x + 8 = 10

x = 10 - 8

x = 2