Question

REZOLVARE COMPLETA.
Sa se determine toate nr.naturale de trei cifre in baza 10 care impartite la 25 dau catul de 6 ori mai mare decat restul.

Answer 1

 [tex]\overline{abc}:25= 6r (rest.\;\;r=\{0;1;2;3;...;24\})\\ \downarrow\\ pt.\,r=0\;\;\;\overline{abc}=25\cdot6\cdot0+0=0\;\;nu\,ne\,convine;\\ pt.\,r=1\;\;\;\overline{abc}=25\cdot6\cdot1+1=151\,;\\ ,,\;\;r=2\;\;\;\overline{abc}=25\cdot6\cdot2+2=302\,;\\ ,,\;\;r=3\;\;\;\overline{abc}=25\cdot6\cdot3+3=453\,;\\ .........................................................\\ ,,\;\;r=24\;\;\overline{abc}=25\cdot6*24+24=3624\,; [/tex]