Question

Rezolvare va rog !!!!​

Answer 1

Răspuns:

$-2\sqrt{2}$

Explicație pas cu pas:

$x+y=-2\sqrt{3} \\\\x^{2} -y^{2} =4\sqrt{6} \\\\x^{2} -y^{2} =(x+y)(x-y)=> (x-y)=\frac{x^{2} -y^{2}} {(x+y)} \\\\(x-y)=\frac{4\sqrt{6} }{-2\sqrt{3} } =-2\sqrt{2}$