Question

rezolvarea completă :)

Answer 1

[2(3x+11)+6(x-7)]/12<(5x-1)/12-13/6
(6x+22+6x-42)/12<(5x-1-26)/12                   ·12
12x-20<5x-27
12x-5x<-27+20
7x<-7
x<-7/7
x<-1
x∈(-α,-1)

Answer 2

$\frac{3x+11}{6} + \frac{x-7}{2} < \frac{5x-1}{12} -2 \frac{1}{6}$
$\frac{3x+11}{6} + \frac{x-7}{2} < \frac{5x-1}{12} - \frac{13}{6}$
(inmultim ambii membri ai inecuatiei cu 12 si obtinem:)

2(3x+11) + 6(x-7) < 5x-1 - 2(13)
6x+22 + 6x-42 < 5x-1 - 26
12x - 20 < 5x - 27
12x - 5x < -27 - 20
7x < -47
x < -47 : 7
x < -6,714

x ∈ ( -∞ , -6,714 )