Question

Rezolvați: (1-2x√2)^2=8

Answer 1

(1-4x radical 2+4x^2·2)=8
1-4x radical 2+8x^2=8
8x^2-4x radical 2+1=8
8x^2-4x radical 2-7=0

delta=32+224
delta=256

x1=4 radical 2+16/2=4(radical2+4)/2=2 radical2+8

x2=4 radical2-16/2=4(radical2-4)/2=2 radical2-8

8(x-2radical2+8)(x-2radical2-8)

Sper sa fie corect si sa te fi ajutat cu ceva :) daca nu voi incerca din nou :)