Question

Rezolvati ecuatia:
[72:(48-x)+58]:10=14

Answer 1

$\displaystyle [72:(48-x)+58]:10=14 \\ 72:(48-x)+58=14*10 \\ 72:(48-x)+58=140 \\ 72:(48-x)=140-58 \\ 72:(48-x)=82 \\ 48-x= \frac{72}{82} \\ 3936-82x=72 \\ -82x=72-3936 \\ -82x=-3864 \\ x= \frac{3864}{82} ^{(2}\Rightarrow \boxed{x= \frac{1932}{41} }$