Question

Rezolvati ecuatia(o sa pun / ca ,,supra" la urmatoarele fractii):x+1/2 + x+5/3 + x+11/4 + x+19/5 + x+29/6 + x+41/7 + x+55/8 + x+71/9 + x+89/10 = 45
Ajutati-ma va rog pentru ca asta o sa imi dea la olimpiada de la matematica.Repede va rog!!!

Answer 1

x+1/2 +x+5/3 +x+19/5 +x+29/6+x+41/7+x+55/8+x+71/9+x+89/10=45
8x+1/2+5/3+19/5+29/6+41/7+55/8+71/9+89/10=45
8x+2/6+10/6+19/5+29/6+41/7+55/8+71/9+89/10=45
8x+16/6+19/5+29/6+41/7+55/8+71/9+89/10=45
8x+16*5/30+19*6/30+29*5/30+41/7+55/8+71/9+89/10=45
8x+80/30+114/60+145/30+41/7+55/8+71/9+89/10=45
8x+339/30+41/7+55/8+71/9+89/10=45
8x+339/30+89*3/30+41/7+55/8+71/9=45
8x+339/30+30/30+41/7+55/8+71/9=45
8x+369/30+41*8/56+55*7/56+71/9=45
8x+369/30+328/56+385/56+71/9=45
8x+369/30+713/56+71/9=45
8x+36*504/15120+713*270/15120+71*1680=45
8x+18144/15120+192510/15120+119280/15120=45
8x+329934/15120=45
8x=45-329934/15120
8x=45*15120/15120-329934/15120
8x=680400/15120-329934/15120
8x=350466/15120
x=350466/15120*1/8
x=350466/15120*8
x=350466/1890
x=185.43