Question

Rezolvati ecuatiile:
a)125+$\frac{x}{4}$-$\frac{1}{4}$=200
b)x-$\frac{2}{3}$-$\frac{5}{6}$=$\frac{1}{2}$

Answer 1

$a) \\ 125+\frac{x}{4}-\frac{1}{4}=200 \\ \frac{125*4+x}{4}-\frac{1}{4}=200 \\ \frac{500+x}{4}-\frac{1}{4} =200 \\ \frac{x+499}{4}=200 \\ x+499=200*4 \\ x+499=800 \\ x=800-499 \\ x=301 \\ b) \\ x-\frac{2}{3}-\frac{5}{6}=\frac{1}{2} \\ \frac{x*3-2}{3}-\frac{5}{6}=\frac{1}{2} \\\frac{3x-2}{3}-\frac{5}{6}=\frac{1}{2} \\\frac{(3x-2)*2-5}{6}=\frac{1}{2} \\ \frac{6x-9}{6}=\frac{1}{2} \\ \frac{3*(2x-3)}{6}= \frac{1}{2} \\ \frac{3*(2x-3)}{6}-\frac{1}{2}=0 \\ \frac{2x-3-1}{2}=\frac{2x-4}{2}=\frac{2*(x-2)}{2}=0$
$2*(x-2)=0*2 \\ 2*(x-2)=0 \\ x-2=0:2 \\ x-2=0 \\ x=0+2 \\ x=2$