Question

rezolvați ecuatiile in Q:a) 7(2x-1)-3(4x-1)=5(3x+2)-1; b)11(x+2)-2(2-5x)=8(3+4x)+5 ;c)3[2(x+4)-3(x-5)=4[3(x+2)-4(x+1)]+15 ;ajutați-ma vă rog

Answer 1

Răspuns:

Explicație pas cu pas:

a) 7(2x - 1) - 3(4x - 1) = 5(3x + 2) - 1

14x - 7 - 12x + 3 = 15x + 10 - 1

2x - 4 = 15x + 9

15x - 2x = -4 - 9

13x = -13

x = -13 : 13

x = -1

b) 11(x + 2) - 2(2 - 5x) = 8(3 + 4x) + 5

11x + 22 - 4 + 10x = 24 + 32x + 5

21x + 18 = 29 + 32x

32x - 21x = 18 - 29

11x = -11

x = -11 : 11

x = -1

c) 3[2(x + 4) - 3(x - 5)} = 4[3(x + 2) - 4(x + 1)] + 15

3(2x + 8 - 3x + 15) = 4(3x + 6 - 4x - 4) + 15

3(23 - x) = 4(2 - x) + 15

69 - 3x = 8 - 4x + 15

69 - 3x = 23 - 4x

4x - 3x = 23 - 69

x = -46