Question

Rezolvați ecuațiile. Mulțumesc mult !!!

Answer 1

Salutare!

$\bf h)\: 0,(3)x+ 1,5=1$

$\bf \dfrac{3}{9}\cdot x+ \dfrac{15}{10}=1$

$\bf \dfrac{\not3}{\not9}\cdot x+ \dfrac{\not15}{\not10}=1$

$\bf \dfrac{1}{3}\cdot x+ \dfrac{3}{2}=1\:\:\:|\cdot 6$

$\bf 6\cdot\dfrac{1}{3}\cdot x+ 6\cdot\dfrac{3}{2}=6\cdot 1$

$\bf \not6\cdot\dfrac{1}{\not3}\cdot x+ \not6\cdot\dfrac{3}{\not2}=6$

$\bf 2x+9=6$

$\bf 2x=6-9$

$\bf 2x=-3$

$\boxed{\bf x=-\dfrac{3}{2}}$

$\bf g)\: 3+|3x-1|=5$

$\bf |3x-1|=5-3$

$\bf |3x-1|=2$

$\bf 3x-1=2\Rightarrow 3x=2+1\Rightarrow 3x=3\:|:3\Rightarrow\boxed{\bf x_{1}=1}$

$\bf 3x-1=-2\Rightarrow 3x=-2+1\Rightarrow 3x=-1\Rightarrow\boxed{\bf x_{2}=-\dfrac{1}{3}}$

Answer 2

Hey! Am ataşat rezolvarea. :)