Question

Rezolvati ecuatile:
3+x=28:4
5(x+2)=32
2a-3=17
8y+6=42-4
20+3t=100:2

Answer 1

3+x=28/4
3+x=7
x=4

5(x+2)=32
5x+10=32
5x=22
x=22/5

2a-3=17
2a=20
a=10

8y+6=42-4
8y-6=38
8y=32
y=4

20+3t=100/2
20+3t=50
3t=30
t=10

Answer 2

1) 3+x=28:4
3+x=7
x=7-3
x=4

2) 5(x+2)=32
5x+10=32
5x=32-10
5x=22 /:5
x=4,4

3) 2a-3=17
2a=17-3
2a=14 /:2
a=7

4)8y+6=42-4
8y+6=38
8y=38-6
8y=32 /:8
y=4

5) 20+3t=100:2
20+3t=50
3t=50-20
3t=30 /:3
t=10