Question

Rezolvati in multimea numerelor reale ecuatiile:
a) 3x+4(x-3)=2x+13
b) 7(x-1)-3(x-2)=x-11
c) 2x-5(x-4)=3(x+2)
d) 9x+1-5(x-1)=2(2x+3)
e) 3(2x-5)+7=6-(x+2)

Answer 1

a)3x+4(x-3)=2x+13
3x+4x-12=2x+13
7x-12=2x+13
5x=25
x=5

b)7(x-1)-3(x-2)=x-11
7x-7-3x+6=x-11
4x-1-x+11=0
3x+10=0
3x=-10
x=-10/3

c)2x-5(x-4)=3(x+2)
2x-5x+20=3x+6
-3x+20-3x-6=0
-6x+14=0
-6x=-14
x=14/6=7/3

d)9x+1-5(x-1)=2(2x+3)
9x+1-5x+5=4x+6
4x+6=4x+6
Nu,are,radacini,reale.

e)3(2x-5)+7=6-(x+2)
6x-15+7=6-x-2
6x-8=4-x
6x-8-4+x=0
7x-12=0
7x=12
x=12/7

Answer 2

 3x+4(x-3)=2x+13
7x−12=2x+13
5x=25
x=5

7(x-1)-3(x-2)=x-11
4x−1=x−11
3x=−10
x=−10/3

2x-5(x-4)=3(x+2)
−3x+20=3x+6
−6x=−14
x=7/3

9x+1-5(x-1)=2(2x+3)
4x+6=4x+6
0=0 Orice număr real poate fi soluție.

3(2x-5)+7=6-(x+2)
6x−8=−x+4
7x=12
x=12/7