Question

Rezolvati in multimea numerelor reale inecuatia:
2(x+1)<$\sqrt{5}$(x+1)

Answer 1

$2(x+1) < \sqrt5 (x+1) \\ \\ 2(x+1) - \sqrt5 (x+1) < 0 \\ \\ (x+1)(2- \sqrt 5) < 0\Big| : (2 - \sqrt5), \quad \Big(2-\sqrt 5<0\Big) \\ \\ x+1 > 0 \\ \\ x > -1 \\ \\ \boxed{x \in (-1, \infty)}$