Question

Rezolvati in multimea numerelor reale inecuatia: $2x+2 \leq \sqrt{5} x + \sqrt{5}$

Answer 1

Dam factor comun in ambele parti 2(x+1) $\leq$ $\sqrt{5}$(x+1)     | ÷(x+1)        rezulta 2 $\leq$ $\sqrt{5}$ rezulta $\sqrt{4} \leq \sqrt{5}$