Question

rezolvati in multimea numerelor reale prin metoda reducerii sistemulde ecuatii:3x+2y=19,x+5y=15

Answer 1

3x+2y=19 X+5y=15 /*(-3) 3x+2y=19 -3x-15y=-45 -15y+2y=-45+19 -13y=-26 Y=-26/-13 Y=2 X+5y=15 X+5*2=15 X+10=15 X=15-10 X=5