Question

Rezolvati in R ecuatia 2^( x^2+x+0,5 ) - 4 rad2 =0

 

 

^-la puterea

rad-radical

Answer 1

$2^{( x^{2} +x+0,5)} -4 \sqrt{2}=0=> 2^{ (x^{2} +x+0,5)} =4 \sqrt{2} = \sqrt{ 2^{5} }$
Ridicam la patrat si rezulta:
$2^{2( x^{2} +x+0,5)}= 2^{5} =>2 x^{2} +2x+1=5=> x^{2} +x-2=0$
cu solutiile:
$x_{1}=1; x_{2}=-2$