Question

rezolvati in r ecuatia (2x la puterea a 2 -5x)(7x+1)=0

Answer 1

$(2x^2-5x)(7x+1)=0$
$x(2x-5)(7x+1)=0$

$x_1 = 0$
$2x-5 = 0 =\ \textgreater \ x_2 = \frac{5}{2}$
$7x+1=0 =\ \textgreater \ x_3 = - \frac{1}{7}$