Question

Rezolvati in R ecuatia "

a) 1 supra x + 3 supra 5 = 0
b)2 supra x-1 + 7x-2 supra x-1 = 2
c) x+2 supra x+3 - 2x-1 supra x-3 = -1

Answer 1

$\dfrac{1}{x} +\dfrac{3}{5} =0 \Leftrightarrow \dfrac{1}{x} = \dfrac{-3}{5}\Leftrightarrow x=\dfrac{5\cdot1}{-3} \Leftrightarrow x= -\dfrac{5}{3}$