Question

Rezolvati in R ecuatia :
radical(2x+3)la puterea2 =5

Answer 1

$\sqrt{ (2x+3)^{2} }=5$
l2x+3l=5
Cazul 1:
2x+3=5
x=1∈R
Cazul 2:
2x+3=-5
x=-4∈R
R/S:S={1;-4}

Answer 2

$\displaystyle \sqrt{(2x+3)^2} =5 \\ |2x+3|=5 \\ 2x+3=5 \\ 2x=5-3 \\ 2x=2 \\ x= \frac{2}{2} \\ x=1 \\ 2x+3=-5 \\ 2x=-5-3 \\ 2x=-8 \\ x=- \frac{8}{2} \\ x=-4 \\ S=\{-4;1\}$