Question

Rezolvati in Z ecuatia.
1 supra lui x +1 supra lui x-1 =2 supra lu x+1,,multumesc

Answer 1

1 supra x+1 x x-1 supra 1=2 supra x+1 eliminam numitorii
x-1=2
x=3

Answer 2

$\underbrace{\frac{1}{x}+\frac{1}{x-1}}_{\frac{\not{x}-1+\not{x}}{x(x-1)}}=\frac{2}{x+1}$
[tex](-1)\cdot{(x+1)}=2\cdot{x}(x-1)\\ -x-1=2x^2-2x\\ 2x^2-x+1=0\;\;;\;\;\Delta=(-1)^2-4\cdot2\cdot1=1-8\;\ \textless \ \;0\;\\ \rightarrow\;nu \,avem\, solutii\, in\, multimea \,\mathbb{R}[/tex]