Question

Rezolvati inecuatia 5x(a-3)mai mare sau egal 9+a,unde a este numar natural.

Answer 1

$5*(a-3) \geq 9+a \\\\ 5a-15 \geq 9+a \\\\ 5a-a \geq 9+15 \\\\ 4a \geq 24 \ \ \ |:4 \\\\ a \geq 6 \Longrightarrow a \in [6;+\infty)$

Answer 2

5×(a-3)≥9+a⇒5a-15≥9+a⇒5a-a≥15+9⇒4a≥24⇒a≥24/4⇒a≥6
a∈[6,∞)
sucees