Question

Rezolvati-mi va rog...Lectia cu ECUATII REDUCTIBILE LA ECUATII DE FORMA ax+b=0 (EXTINDERE)

Answer 1

ex.1
a) rezulta (4-x)/2=(3+x+8)/2      
4-x=x+11
-x-x=11-4
-2x=7   inmultim cu -1
x=-7/2

b) rezulta 24x-x-1=2x-1
23x-2x=-1+1
21x=0
x=0

c)rezulta 16x+2-3(x-1)=9(-x+1)
16x+2-3x+3=-9x+9
13x+9x=9-5
22x=4
x=4/22=2/11
x=2/11

d)2 intreg 1/9=19/9
2,0(5)=(205-20)/90=185/90=34/18
rezulta 18+6(2x-1)-38=34
12x-6-20=34
12x=34+6+20
x=60/12
x=5

e) rezulta 6(x+1)+4(x+2)+3(x-3)=0
6x+6+4x+8+3x-9=0
13x+5=0
13x=-5
x=-5/13

f)1,1(6)=(116-11)/90=105/90=21/18=7/6
2 intreg 1/2=5/2
7x/6-5/2(x+2)=5x-9
7x-15(x+2)=6(5x-9)
7x-15x-30=30x-54
-8x-30x=30-54
-38x=-24    inmultim -1
x=24/38=12/19
x=12/1*

g) 1,5=15/10=3/2
3/2+(x-1)/4=x/2+(5-10x)/4
6+x-1=2x+5-10x
x+5=-8x+5
x+8x=5-5
9x=0
x=0

i) 0,2=2/10=1/5
(x-3)/2-10(1-3x)+1=[3(2-x)/2]/2-7
(x-3)/2-10+30x+1=(6-3x)/4-7
2(x-3)+4(30x-9)=6-3x-28
2x-6+120x-36=-3x-22
122x+3x=-22+42
125x=20
x=20/125=4/25
x=4/25

j)  1 intreg 1/4=5/4
18 intreg 1/3=55/3
22 intreg 2/3=68/3
0,5=5/10=1/2
1,25=125/100=25/20=5/4
2,25=225/100=45/20=9/4
rezulta [1/2:5/4+7/5:5/4-x]/[(9/4+1/4):55/3]=68/3
[1/2·4/5+7/5·4/5-x]/[10/4·3/55]=68/3
[2/5+28/25-x]/(30/220)=68/3
[(10+28)/25-x]/(3/22)=68/3
(38/25-x)/((3/22)=68/3
[(38-25x)/25]:3/22=68/3
(38-25x)/25·22/3=68/3
22(38-25x)/75=68/3
66(38-25x)=75·68
38-25x=5100/66
-25x=2550/33
-x=2550/33·1/25
-x=102/33    inmultim -1
x=-34/11

k) rezulta x²-2√2x+2-(x²-2)=x+1
x²-x²-2√2x+2+2=x+1
-2√2x-x=1-4            inmultim -1
x(2√2+1)=3
x=3/(2√2+1)
x=3(2√2-1)/(8-1)
x=3(2√2+1)/7

l) rezulta √2x-x+√3x-√2x+√3-√2+√4x-√3x+2√4-2√3=3-√2
√2x-√2x+√3x-√3x+2x-x+√3-√2+4-2√3=3-√2
x-√3-√2+4=3-√2
x=3-√2+√3+√2+4
x=7+√3

m) rezulta (0,25-x/4)=0,75
-x/4=0,75-0,25
-x/4=0,5       
-x=0,5·4
-x=2   inmultim -1
x=-2