Question

rezolvati prin metoda substitutiei sistemele

Answer 1

2x-4y=0 => 2x=4y => x=2y

$\frac{x+2}{10} - \frac{2y+1}{3} =-2$

$\frac{2y+2}{10}- \frac{2y+1}{3}=-2$

$\frac{2(y+1)}{10} - \frac{2y+1}{3}=-2$

$\frac{y+1}{5} - \frac{2y+1}{3}=-2$

$\frac{3(y+1)-5(2y+1)}{15}=-2$

3y+3-10y-5=-30

-7y-2=-30

-7y=-30+2

-7y=-28 

$=\ \textgreater \ y=\frac{28}{7}=4$

x=2y => x=2·4=8