Question

Rezolvati prin metoda substitutiei sistemul:

y-V2x=0
5x+V8y=9


V-este radical

Answer 1

$\left\{\begin{matrix} y - \sqrt{2} x = 0\\ 5x + \sqrt{8} y = 9\end{matrix}\right.$

$y = 0 + \sqrt{2} x$

$y = \sqrt{2} x$

$5x + \sqrt{8} y = 9$

$5x + \sqrt{8} \times \sqrt{2} x = 9$

$5x +\sqrt{8 \times 2} x = 9$

$5x + \sqrt{16} x = 9$

$5x + 4x = 9$

$9x = 9\:|\div9$

$x=1$

$y = \sqrt{2} x$

$y = \sqrt{2} \times 1$

$y = \sqrt{2}$