Question

rezolvati repede va rog !!
( 5 la puterea a doua + 2 la puterea a doua ) : 29 - ( 5 la puterea a treia inmultit cu 3 la puterea a treia ) : 15 la puterea a cincea =
dau coroana

Answer 1

(5^2+2^2):29-(5^3×3^3):15^5=
(25+4):29-(15^6):15^5=
29:29-(15^6):15^5=
1-(15^6):15^5=
1-15^1=
1-15=14

Answer 2

(5^2+2^2)÷29-(5^3×3^3)÷15^5=
(25+4)÷29-[(5×3)^3]÷15^5=
29÷29-15^3÷15^5=
1-15^(3-5)=
1-15^-2=
1-(1/15)^2=
1-1/225=
amplifici pe 1 cu 225
225-1=224