Question

rezolvati sistemul de ecuatii:
3(x-1)+4=5y
x-8(y+0,5)=2

x^2-4(y+2)=(x-5)^2
3x-y=0

Answer 1

Răspuns:

1. 3(x-1)+4=5y

x-8(y+0,5)=2

3(x-1)+4=5y

x-6+8y

3(6+8y-1)+4=5y

y= - 1

x=6+8(-1)

x=-2

(x,y)=(-2,-1)

3(-2-1)+4=5(-1)

-2-8(+1+0.5)=2

-5=-5

2=2

(x,y)=(-2,-1)