Question

Rezolvați URGENT ex de sus!

Answer 1

$\it b) m_a-m_g\geq m_g-m_h \Rightarrow m_a-m_g\geq m_g-\dfrac{m_g^2}{m_a}\Big|_{\cdot m_a}\Rightarrow\\ \\ \Rightarrow m_a^2- m_am_g\geq m_am_g-m_g^2\Rightarrow m_a^2+m_g^2-2m_am_g\geq0 \Rightarrow (m_a-m_g)^2\geq0\ (A)$