Question

Rezolvati urmatoarele exerciții {111-[408:(x-5)+260]:3}×9+32=239 rezultatul trebuie sa fie 107 e cu mersul invers amandoua 100×{100:(100-a×2)]}+100=600 rezultatul trebuie sa fie 10 tot cu mersul invers .... ajutatima va rog repedeeeeeeeeeeeeeee dau coroana Mulțumesc stelute inimi si 20 puncte

Answer 1

{111-[408:(x-5)+260]:3}x9+32=239
{111-[408:(x-5)+260]:3}x9=239-32
{111-[408:(x-5)+260]:3}x9=207
{111-[408:(x-5)+260]:3}=207:9
111-[408:(x-5)+260]:3=23
[408:(x-5)+260]:3=111-23
[408:(x-5)+260]:3=88
408:(x-5)+260=88x3
408:(x-5)+260=264
408:(x-5)=264-260
408:(x-5)=4
x-5=408:4
x-5=102
x=102+5
x=107

100x[100:(100-ax2)]+100=600
100x[100:(100-ax2)]=600-100
100x[100:(100-ax2)]=500
100:(100-ax2)=500:100
100:(100-ax2)=5
100-ax2=100:5
100-ax2=20
ax2=100-20
ax2=80
a=80:2
a=40

Answer 2

{111-[408:(x-5)+260]:3}×9=239-32
{111-[408:(x-5)+260]:3}×9=207
111-[408:(x-5)+260]:3=207:9
111-[408:(x-5)+260]:3=23
[408:(x-5)+260]:3=111-23
[408:(x-5)+260]:3=88
408:(x-5)+260=88×3
408:(x-5)+260=264
408:(x-5)=264-260
408:(x-5)=4
x-5=408:4
x-5=102
x=102+5
x=107



100×[100:(100-a×2)]+100=600
100×[100:(100-a×2)]=600-100
100×[100:(100-a×2)]=500
100:(100-a×2)=500:100
100:(100-a×2)=5
100-a×2=100:5
100-a×2=20
a×2=100-20
a×2=80
a=80:2
a=40