Question

Rezolvati va rog chit mai rapid!$(2\sqrt{8}+3 \sqrt{5} -7 \sqrt{2})( \sqrt{72}+ \sqrt{20}-4 \sqrt{2}$

Answer 1

$(2\sqrt{2 ^{3} } +3 \sqrt{5} -7 \sqrt{2} ) (\sqrt{(2^{3} *3 ^{2}) } +\sqrt{(2^{2} *5) } -4 \sqrt{2})$
$=(4\sqrt{2 } +3 \sqrt{5} -7 \sqrt{2} ) (6\sqrt{2} } +2\sqrt{5} -4 \sqrt{2})$
$=(3 \sqrt{5}-3\sqrt{2 })(2\sqrt{2} } +2\sqrt{5})$
$=(6 \sqrt{10}+30-12-6 \sqrt{10})$
=18

Answer 2

$(2\sqrt{8}+3\sqrt{5}-7\sqrt{2})*(\sqrt{72}+\sqrt{20}-4\sqrt{2}=\\(\sqrt{2^{2}*8}+\sqrt{3^{2}*5}-\sqrt{7^{2}*2})*(\sqrt{72}+\sqrt{20}-\sqrt{4^{2}*2})=\\(\sqrt{32}+\sqrt{45}-\sqrt{98})*(\sqrt{72} +\sqrt{20}-\sqrt{32})=\\2,4655632453..*7,3005630798..=18$