Question

Rezolvati va rog in R acuatia:$x^{2} -3x+1=5$

Answer 1

[tex]x^2-3x+1=5\\ x^2-3x+1-5=0\\ x^2-3x-4=0\\ \triangle=b^2-4ac=(-3)^2-4\cdot(-4)=9+16=25\\ x_{1/2}= \frac{-b\pm\sqrt{\triangle}}{2a} = \frac{3\pm 5}{2} \\ x_1= \frac{3+5}{2}=4\\ x_2= \frac{3-5}{2} = \frac{-2}{2} =-1[/tex]