Question

rezolvazi va rog acest sistem

{3x-5<x-2
{3x+21>= 3(x+1)^2

Answer 1

2x<3=> x<3/2
3x+21>=3x^2+6x+3
0>=3x^2+3x-18 | impartim la 3
0>=x^2+x-9
∆=1+36=37
x1,x2=(-1+-√37)/2. √37= aprox 6
x1=-(1+6)=5/2
x2=(-1-6)/2=-7/2
in a doua ecuatie ca sa fie mai mic sau egal cu 0 intervaluk este intre radacini
x<3/2
-7/2<=x<=5/2 intersectam cele doua ecuatii
R: -7/2<=x<3/2