Question

rezultatele sunt 26) a=1 si b =2, (b-a)^2003=1      ......27) a=4

Answer 1

[tex](4+8+12+...+4000):(2+4+6+...+2000)+(2011+37):2^{10}= \\ \\ 4(1+2+3+...+1000):2(1+2+3+....+1000)+2048:2^{10}= \\ \\ 4 \frac{1000(1000+1)}{2}: 2 \frac{1000(1000+1)}{2}+2^{11}:2^{10}= \\ \\ (4:2) \frac{1000(1001+1)}{2}* \frac{2}{1000(1001+1)} +2= \\ \\ 2*1+2=4[/tex]

Ti-am facut 27 pt. ca la 26 nu vad puterile bine si risc sa gresesc.
P.S:Unghia mamei tale(cea de la degetul inelar) cred ca pusa invers.