Question

Rezultatul calculului 11+22+33+....+1100 weste egal cu.....am nevoie urgent....multumesc

Answer 1

11(1 + 2 +3 +..........+100) = 11·100·101:2 = 11·50·101 = 55550

Answer 2

Scriem operatia asa cum este:$11+22+33+....+1100$ Dam factor comun pe 11 si avem $11(1+2+3+...+100)$ Aplicam Suma lui Gauss[n*(n+1)]/2:[tex]11[100*(100+1)]/2=\ \textgreater \ 11(100*101)/2=\ \textgreater \ 5050*11=\ \textgreater \ \\ S_n= 55550[/tex]