Question

Rezultatul calculului 6 radical din 18 + 12 radical din 8 - 11 radical din 32

Answer 1

6√2x3²+12√2²x2-11√2⁴x2
6x3√2+12x2√2-11x4√2
√2(18+24-44)=√2(42-44)=√2x(-2)

Answer 2

    
[tex]6 \sqrt{18} +12 \sqrt{8} -11 \sqrt{32} = \\ 6 \sqrt{9 \times 2} +12 \sqrt{4 \times 2} -11 \sqrt{16 \times 2} = \\ 6 \times 3 \sqrt{2} +12 \times 2 \sqrt{2} -11 \times 4 \sqrt{2} = \\ 18\sqrt{2} +24 \sqrt{2} -44 \sqrt{2} = 42\sqrt{2} -44 \sqrt{2} = \boxed{-2\sqrt{2}}[/tex]