Question

Sa se afle 4 nr naturale consecutive care au suma 222

Answer 1

a+b+c+d=222
b=a+1
c=a+2
d=a+3

a+a+1+a+2+a+3=222
ax4+6=222/-6
ax4=216/:4
a=54

Answer 2

a+(a+1)+(a+2)+(a+3)=222
4a=222-6
4a=216
a=216:4
a=54 primul nr.
54+1=55 al II-lea nr.
54+2=56 al III-lea nr.
54+3=57 al IV-lea nr.
54+55+56+57=222 suma celor 4 numere consecutive