Question

Sa se afle suma a+b stiind ca m+n=14 si am+bm+an+bn=126,undw a,b,m si n sunt numere naturale nenule.

Answer 1

$am+bm+an+bn=126 \\ \\ m(a+b)+n(a+b)=126 \\ \\ (a+b)(m+n)=126 \\ \\ (a+b) \cdot 14=126 \Rightarrow \boxed{a+b=9}~.$

Answer 2

m[a+b]+n[a+b]=126
⇒[a+b]·[m+n]=126
⇒a+b=126/14⇒a+b=9;