Question

Sa se afle ultima cifră a numerelor :


$a) {9}^{131}$
$b) {6}^{72} - {4}^{13}$
$c) {7}^{179} + {8}^{234}$
$d) {2}^{1516} + {8}^{301} + {7}^{202}$
$e) {2}^{78} \times {6}^{80}$
$f) {3}^{100} \times {5}^{16}$
$g) {5}^{49} + {2}^{83}$
$i) {6}^{81} \times {4}^{19} + {3}^{50}$
​

Answer 1

Explicație pas cu pas:

●u(9¹³¹)=9 u=9

●u(6⁷²-4¹³)=6-4=2 u=2

=u(6⁷²)=6

=u(4¹³)=4

●u(7¹⁷⁹+8²³⁴)=3+4=7 u=7

=u(7¹⁷⁹)=3

=u(8²³⁴)=4

●u(2¹⁵¹⁶+8³⁰¹+7²⁰²)=6+2+6=14 u=4

=u(2¹⁵¹⁶)=6

=u(8³⁰¹)=2

=u(7²⁰²)=6

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