Question

Să se calculeze:
a) 4⁻² + 2⁻³ + [(-2)³]⁻¹ =
b) ( $\frac{2}{3}$ ⁻² - (-2 $\frac{1}{2}$ )⁻¹ + (- $\frac{5}{2}$ ) ⁻² =
la a doua este -2 intregi si 1/2
Vă rog ajutati-ma.

Answer 1

4⁻²=1/(4)²=1/16
2⁻³=1/(2)³=1/8
[(-2)³]⁻¹=(-8)⁻¹=-1/8

a)1/16 + 1/8 - 1/8 = 1/16
b)[(3/2)² + 5/2]⁻¹ - (2/5)²=
(9/4 + 5/2)⁻¹ - 4/25=
4/19 - 4/25=
(4x25-4x19)/475=
24/475