Question

sa se calculeze aria triunghiului MNP, stiind ca MN= 3 rad din 2 , NP=4 si m(MNP)= 45 grade

Answer 1

aria= [ MN ·NP·sin45} /2= [ 3√2·4·√2/2  ]/ 2= 12 :2= 6

Answer 2

           
$A_{\Delta MNP}= \frac{MN*NP*sin(\ \textless \ MNP)}{2} = \frac{3 \sqrt{2} *4*sin\,45^o}{2}= \\ \\ =\frac{12 \sqrt{2} * \frac{ \sqrt{2} }{2} }{2}= \frac{12 \sqrt{2}*\sqrt{2} }{4} = \frac{12*2}{4}= \frac{24}{4} =\boxed{6\; cm^2 }$