Question

Sa se calculeze cos x, stiind ca sin x=12supra13si x apartine(0°,90;°)

Answer 1

$cosx= \sqrt{1-sin^2x}= \sqrt{1-( \frac{12}{13})^2 }= \sqrt{1- \frac{144}{169} }= \sqrt{ \frac{25}{169} }= \frac{5}{13}$

Answer 2

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