Question

Sa se calculeze ecuatia \sqrt{3x + 19} - \sqrt{x + 2} = \sqrt{x + 7} [/tex]

Answer 1

$\sqrt{3x+19} - \sqrt{x+2} = \sqrt{x+7}|^{2}$

$(\sqrt{3x+19})^{2} -( \sqrt{x+2}) ^{2} = (\sqrt{x+7})^{2} \\ \\ 3x+19-(x+2)=x+7 \\ \\ 3x+19-x-2=x+7 \\ \\ 2x+17=x+7 \\ \\ x=-10$