Question

Sa se calculeze masa de Ca3(Po4)2 care contine 1200g Ca

Answer 1

M Ca3(PO4)2 = 310.17 g/mol
m Ca3(PO4)2 = 1200 g

asadar:

310.17 g Ca3(PO4)2 contine 3 x 40 g/mol Ca adica 120 g Ca
atunci 
1200 g Ca3(PO4)2 contine a g Ca
a = ( 1200 x 120 ) / 310.17 => a= 464.3 g Ca

Answer 2

Ca3 (PO4)2               M=3.40+2.31+8.16=310-------->1mol=310g                  310gCa3(PO4)2-------------120 g Ca                                                                       xg-----------------------------------1200g Ca                                                          x=310.1200:120=3100 g fosfat de calciu