Question

Să se calculeze perimetrul triunghiului ABC cu vârfurile A(1,1), B(2,2), C(1,2) . Help me, please! :/

Answer 1

AB=√(xB-xA)²+(yB-yA)²

AB=√(2-1)²+(2-1)²

AB=√1²+1²

AB=√1+1

AB=√2

BC=√(xC-xB)²+(yC-yB)²

BC=√(1-2)²+(2-2)²

BC=√(-1)²+0²

BC=√1

BC=1

AC=√(xC-xA)²+(yC-yA)²

AC=√(1-1)²+(2-1)²

AC=√0²+1²

AC=√1

AC=1

PΔABC=AB+BC+AC

PΔABC=√2+1+1

PΔABC=2+√2

Answer 2

    Baftă!

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